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April 16, 2014

April 16, 2014

Posted by **Andrea** on Monday, December 10, 2012 at 9:53am.

How many "mathematical" solutions does this problem have? What is the feasible number of burgers and cans of spinach purchased?

When the guys got home, Olive Oyl (a stingy harridan) nagged them about spending $2.98 per can of spinach and $4.58 per burger (without fries!). With 6% sales tax, what was the total spent?

- math -
**Steve**, Monday, December 10, 2012 at 10:45am2b^2+s^2 = 59

2s^2+b^2 = 43

b^2 = 43-2s^2, so

2(43-2s^2)+s^2 = 59

3s^2 = 27

s=±3

so, b=±5

Only positive values are "feasible", so

s=3,b=5

(2.98*3 + 4.58*5)*1.06 = 33.75

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