Posted by riza on Monday, December 10, 2012 at 5:59am.
If the height is h, and the near end of the canal is x,
h/x = tan 52.75°
h/(x+100.6) = tan 38.5°
equating the two values for x, we have
h/tan52.75° = h/tan38.5° - 100.6
h/1.315 = h/0.795 - 100.6
h = 202.25
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