Posted by ifi on .
use implicit differentiation to find dy/dx and then d^2y/dx^2.
y^2=ye^x^2+2x
ans for dy/dx= [2(xye^x^2 + 1)]/(2ye^x^2)
after that i don't know how to proceed. can someone show me the steps(x need for calculation) and final answer. i try to use wolfram but it give me a weird ans( maybe i don't know how to input this formula).

math 
Steve,
It's nasty, but you gotta use the quotient rule, substituting in y' as needed:
y'' =
[[(ye^x^2 + xy'e^x^2 + xy(2xe^x^2))(2ye^x^2)]
 [(xye^x^2 + 1)(2y'  2xe^x^2)]]
/ (2ye^x^2)^2
EEEK! After substituting in for y', it's nasty.
Glad it's not MY homework!