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January 30, 2015

January 30, 2015

Posted by **Please Help :)** on Monday, December 10, 2012 at 1:35am.

- Intermediate Algebra -
**Reiny**, Monday, December 10, 2012 at 9:26amspeed of slower car --- x

speed of faster car ---- x+5

time of slower car to go 30 miles = 30/x

time of faster car to go 45 miles = 45/(x+5)

but they are the same, so ---

45/(x+5) = 30/x

45x = 30x + 150

15x = 150

x = 10

so the slow car goes 10 mph (very slow) and the faster car goes 15 mph

check:

at 10 mph, it takes 30/10 or 3 hrs to got 30 miles.

at 15 mph , to go 45 miles, takes 45/15 = 3 hrs

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