Posted by **Hshdhdhdhdjdjdjdjjsjshsgshshs** on Monday, December 10, 2012 at 12:57am.

the acceleration of a car is 2m/s^2 and another car has constant velocity of 35m/s.what time the first car overtake the car with constant velocity of the first car?

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- physics math -
**Reiny**, Monday, December 10, 2012 at 9:00am
first car:

a = 2 m/s^2

v = 2t + c

when t = 0 , v = 0 m/s

0 = 0 + c , so c=0

so v = 2t

d = t^2 + k

when t = 0, d = 0

0 = 0 + k, so k=0

for 1st car: d = t^2

2nd car:

v = 35

d = 35t + c

when t= 0 , d = 0 , so c = 0

for 2nd car : d = 35t

so we want t^2 = 35t

t^2 - 35t = 0

t(t-35) = 0

t = 0 , (at the start they both had traveled no distance)

or

t = 35

the 1st car will catch the second car in 35 seconds

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