Posted by Nancy on .
A 10.0 g sample of ice at 14.0°C is mixed with 124.0 g of water at 81.0°C. Calculate the final temperature of the mixture assuming no heat loss to the surroundings. The heat capacities of H2O(s) and H2O(l) are 2.08 and 4.18 J/g°C, respectively, and the enthalpy of fusion for ice is 6.02 kJ/mol.

Chemisrty 
DrBob222,
q1 = heat to raise T of ice from 14.0 C to zero C.
q1 = mass ice x heat capacity ice x (TfTi) where Tf is 0 and Ti = 14.
q2 = heat to melt ice
q2 = mass iced x heat fusion.
q3 = heat to raise T of melted ice from zero C to Tfinal.
q3 = mass melted H2O x specific heat H2O x (Tf  Ti) where Tf is the unknown and Ti = 0
q4 = heat released by warm water at 81.0C dropping to Tfinal.
q1 + q2 + q3 + q4 = 0.
Substitute and solve for Tf. Post you work if you get stuck.