Thursday

September 18, 2014

September 18, 2014

Posted by **Nancy** on Sunday, December 9, 2012 at 10:16pm.

- Chemisrty -
**DrBob222**, Monday, December 10, 2012 at 12:48amq1 = heat to raise T of ice from -14.0 C to zero C.

q1 = mass ice x heat capacity ice x (Tf-Ti) where Tf is 0 and Ti = -14.

q2 = heat to melt ice

q2 = mass iced x heat fusion.

q3 = heat to raise T of melted ice from zero C to Tfinal.

q3 = mass melted H2O x specific heat H2O x (Tf - Ti) where Tf is the unknown and Ti = 0

q4 = heat released by warm water at 81.0C dropping to Tfinal.

q1 + q2 + q3 + q4 = 0.

Substitute and solve for Tf. Post you work if you get stuck.

**Answer this Question**

**Related Questions**

biology - A 28.0-g sample of ice at -18.0°C is mixed with 124.0 g of water at 85...

Chemistry - A 14.0-g sample of ice at -18.0°C is mixed with 122.0 g of water at ...

chemistry - A 13.0-g sample of ice at -13.0°C is mixed with 105.0 g of water at ...

Chemistry - A 13.0-g sample of ice at -13.0°C is mixed with 112.0 g of water at ...

Chemistry - A 19.6 g sample of ice at -10.0°C is mixed with 100.0 g of water at ...

Chemistry - A 300.0g sample of ice at -30.OC is mixed with 300.0G of water at ...

Chemistry - A 24.0 g sample of ice at -19.0°C is mixed with 118.0 g of water at ...

chemistry - A 32.0-g sample of water at 290. K is mixed with 51.0 g water at 310...

Chemistry - A 30.0 gram sample of water at 280. K is mixed with 50.0 grams of ...

Chem - 1) A 15.0 g sample of nickel metal is heated to 100.0 C and dropped into ...