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March 30, 2017

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a circle has the equation 3(x-5)^2_3y^2=12. Find the center and radius and graph the circle. find the intercepts, if any.

plz show work

  • college algebra-plz help - ,

    Shouldn't there be a + sign between the 2 and the 3? What you have written is not the equation of a circle.

  • college algebra-plz help - ,

    Yes, my mistake.find the center, radius and graph of circle. then find intercepts

    3(x-5)^2+3y^2=12

    plz show work

  • college algebra-plz help - ,

    divide everybody by 3

    (x-5)^2 + y^2 = 4

    centre : (5,0), radius 2

    clearly the circle can't reach the y-axis,
    (let x= 0, ---> 75 + 3y^2 = 12
    3y^2 = - .... , not possible)

    for the x-intercepts , let y = 0
    3(x-5)^2 = 12
    (x-5)^2 = 4
    x-5 = ± 2
    x = 7 or x = 3

  • college algebra-plz help - ,

    Convert:
    TT/3 rad to degrees

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