Posted by **James** on Sunday, December 9, 2012 at 6:50am.

a circle has the equation 3(x-5)^2_3y^2=12. Find the center and radius and graph the circle. find the intercepts, if any.

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**drwls**, Sunday, December 9, 2012 at 7:19am
Shouldn't there be a + sign between the 2 and the 3? What you have written is not the equation of a circle.

- college algebra-plz help -
**James**, Sunday, December 9, 2012 at 7:28am
Yes, my mistake.find the center, radius and graph of circle. then find intercepts

3(x-5)^2+3y^2=12

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**Reiny**, Sunday, December 9, 2012 at 9:59am
divide everybody by 3

(x-5)^2 + y^2 = 4

centre : (5,0), radius 2

clearly the circle can't reach the y-axis,

(let x= 0, ---> 75 + 3y^2 = 12

3y^2 = - .... , not possible)

for the x-intercepts , let y = 0

3(x-5)^2 = 12

(x-5)^2 = 4

x-5 = ± 2

x = 7 or x = 3

- college algebra-plz help -
**Erna**, Sunday, December 9, 2012 at 9:57pm
Convert:

TT/3 rad to degrees

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