college algebraplz help
posted by James on .
a circle has the equation 3(x5)^2_3y^2=12. Find the center and radius and graph the circle. find the intercepts, if any.
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Shouldn't there be a + sign between the 2 and the 3? What you have written is not the equation of a circle.

Yes, my mistake.find the center, radius and graph of circle. then find intercepts
3(x5)^2+3y^2=12
plz show work 
divide everybody by 3
(x5)^2 + y^2 = 4
centre : (5,0), radius 2
clearly the circle can't reach the yaxis,
(let x= 0, > 75 + 3y^2 = 12
3y^2 =  .... , not possible)
for the xintercepts , let y = 0
3(x5)^2 = 12
(x5)^2 = 4
x5 = ± 2
x = 7 or x = 3 
Convert:
TT/3 rad to degrees