Posted by **Heather** on Sunday, December 9, 2012 at 3:31am.

a circle has the equation

x^2+y^2+6x-6y-46=0

find the center and the radius of the euation. If there are any intercepts list them.

- college algebra, Please help!! -
**drwls**, Sunday, December 9, 2012 at 4:35am
(x+3)^2 + (y-3)^2 = 64 = R^2

The origin is at x=-3 and y=3, and the radius is R=8

For the y intercept, set x=0 in the original equation and solve for y. For the x intercept, set y = 0 and solve for x.

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