college algebra, Please help!!
posted by Heather on .
a circle has the equation
x^2+y^2+6x6y46=0
find the center and the radius of the euation. If there are any intercepts list them.

(x+3)^2 + (y3)^2 = 64 = R^2
The origin is at x=3 and y=3, and the radius is R=8
For the y intercept, set x=0 in the original equation and solve for y. For the x intercept, set y = 0 and solve for x.