Math
posted by Phoebe on .
Please help!!!!!! cosxsin^2x1

So what is the question and I suspect you have a typo

I always get confused working out this problem because I keep getting the wrong answer. cosine of x sin squared x1

and it needs me to write the expression in factored form as an algebraic expression of a single trigonometric function.

sin^2 x = 1  cos^2 x
cos x  (1cos^2 x)  1
cos x  2 + cos^2 x
cos^2 x + cos x  2
as you wrote it
perhaps you mean
cos x  (sin^2 x 1)
cos x  (1 cos^2 x  1)
cos x + cos^2 x
cos x (cos x + 1) 
Where did you get the 1cosine squared from?

Find an algebraic expression equivalent to the given expression. sine (tan inverse of u/2)

For the problem cosine of xsine squared x1 the choices are A)sine squared x, B) (cot x+1)(cot x1), C) (cos x+2)(sin x1), D)(sin x+2)(sin x1)

sin^2 x + cos^2 x = 1 identity
so
sin^2 x = 1  cos^2 x 
(cos/sin +1)(cos/sin1) = cos^2/sin^2  1
====================================
sin[ tan^1(u/2) ]
right triangle
opposite = u
adjacent = 2
so hypotenuse = sqrt(u^2 +4)
so
sin = u/sqrt(u^2+4)
or [u sqrt (u^2+4)] / (u^2+4) 
Thank you for your help. Can you please delete all the questions I have typed in today?