Posted by Michael on Saturday, December 8, 2012 at 6:37pm.
Five Forces act on an object:
1. 60 N at 90 degrees
2. 40 N at 0 degrees
3. 80 N at 270 degrees
4. 40 N at 180 degrees
5. 50 N at 60 degrees
What are the magnitude and direction of a sixth force that would produce equilibrium?

Physics  drwls, Saturday, December 8, 2012 at 11:18pm
Forces 2 and 4 cancel each other.
Forces 1 and 3 combined are the same as
20 N at 270 degrees. First calculate the resultant. The equilibrant will be the opposite of that.
So, add 20 N at 270 and 50 N at 60.
North direction component = 50sin60 = 43.3
East direction component = 20 + 50cos60 = 5
Magnitude = sqrt[43.3^2 + 5^2] = 43.6 newtons
Direction = 6.6 degrees E of N
For the equilibrant, make that 186.6 degrees
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