Wednesday

December 17, 2014

December 17, 2014

Posted by **Michael** on Saturday, December 8, 2012 at 6:37pm.

1. 60 N at 90 degrees

2. 40 N at 0 degrees

3. 80 N at 270 degrees

4. 40 N at 180 degrees

5. 50 N at 60 degrees

What are the magnitude and direction of a sixth force that would produce equilibrium?

- Physics -
**drwls**, Saturday, December 8, 2012 at 11:18pmForces 2 and 4 cancel each other.

Forces 1 and 3 combined are the same as

20 N at 270 degrees. First calculate the resultant. The equilibrant will be the opposite of that.

So, add 20 N at 270 and 50 N at 60.

North direction component = 50sin60 = 43.3

East direction component = -20 + 50cos60 = 5

Magnitude = sqrt[43.3^2 + 5^2] = 43.6 newtons

Direction = 6.6 degrees E of N

For the equilibrant, make that 186.6 degrees

**Answer this Question**

**Related Questions**

physics - Five forces act on an object: 1: 60 N at 90 degrees, 2: 40 N at 0 ...

Physics - Five forces act simultaneously on Point A: the first 60N at 90 degrees...

Physics - If five forces act towards the same point on a body at angles of 60, ...

Calculus - Find the exact values of the following. cos 270 degrees = 90 degrees...

6th grade math - Which expression could you use to find the measure of an angle ...

math - For which angles beta, with 0 degrees less than/equal to beta less than/...

Physics HELP!! - Forces of 11.1N north, 19.9N east, and 14.0N south are ...

Math - Three forces with magnitudes of 70 pounds, 40 pounds, and 60 pounds act ...

Physics - Forces of 11.3N north, 19.1N east, and 14.5N south are simultaneously ...

physics - Forces of 20 N at 80 degrees, and 50 N at an angle of 210 degrees, ...