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March 30, 2015

March 30, 2015

Posted by **Michael** on Saturday, December 8, 2012 at 6:37pm.

1. 60 N at 90 degrees

2. 40 N at 0 degrees

3. 80 N at 270 degrees

4. 40 N at 180 degrees

5. 50 N at 60 degrees

What are the magnitude and direction of a sixth force that would produce equilibrium?

- Physics -
**drwls**, Saturday, December 8, 2012 at 11:18pmForces 2 and 4 cancel each other.

Forces 1 and 3 combined are the same as

20 N at 270 degrees. First calculate the resultant. The equilibrant will be the opposite of that.

So, add 20 N at 270 and 50 N at 60.

North direction component = 50sin60 = 43.3

East direction component = -20 + 50cos60 = 5

Magnitude = sqrt[43.3^2 + 5^2] = 43.6 newtons

Direction = 6.6 degrees E of N

For the equilibrant, make that 186.6 degrees

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