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what is the concentration of the hydroxide ion in a solution if .12 mol of strontium hydroxide are dissolved in water and the final solution volume is 500. mL?

  • chemistry - ,

    From the problem I assume all of the 0.12 mol Sr(OH)2 is dissolved.
    Sr(OH)2 ==> Sr^2+ + 2OH^-
    0.12 mol/0.5L = 0.24M
    Therefore, )Sr^2+) = 0.24M
    (OH^-) = 2*0.24M = 0.48 M.

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