If a sphere and paper are dropped from 10 meters and the sphere hit the ground in 1.4 seconds and the paper hit in 2 seconds, why did the impact time in case of the piece of paper change in comparison to the sphere?
A. a=(Wt-R)/m;a=g B. a=(Wt-R)/m;a>g
C. a=(Wt-R);a<g D. a=(Wt-R)/m;a<g
To understand why the impact time of the piece of paper changed in comparison to the sphere, let's break down the given information and analyze the situation.
We are given that both the sphere and the piece of paper are dropped from a height of 10 meters. The sphere hits the ground in 1.4 seconds, while the paper hits the ground in 2 seconds. This discrepancy suggests that there might be a difference in the acceleration experienced by the sphere and the piece of paper.
The acceleration of an object can be calculated using the formula a = (Wt - R) / m, where:
- a represents acceleration
- Wt represents the weight (force of gravity acting on the object)
- R represents the air resistance
- m represents the mass of the object
From the given answer choices, we need to find the equation that represents the scenario accurately.
Looking at the options:
A. a = (Wt - R) / m; a = g
B. a = (Wt - R) / m; a > g
C. a = (Wt - R); a < g
D. a = (Wt - R) / m; a < g
We know that the acceleration due to gravity is represented by g, and it is approximately 9.8 m/s².
Given that both the sphere and the piece of paper experience the same gravitational force (weight), their accelerations should be the same if we neglect air resistance.
However, the change in impact time between the sphere and the piece of paper suggests that air resistance plays a role. Air resistance can slow down the fall of objects by exerting an opposing force.
Considering this, we can conclude that the correct answer is D. a = (Wt - R) / m; a < g. This choice indicates that the acceleration of the piece of paper is less than the acceleration due to gravity (g) because the impact time is longer.
Therefore, the impact time of the piece of paper changed in comparison to the sphere due to the influence of air resistance, which slows down the fall of the paper more than the sphere.