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October 25, 2014

October 25, 2014

Posted by **Anonymous** on Saturday, December 8, 2012 at 11:59am.

- pre calculus -
**Reiny**, Saturday, December 8, 2012 at 12:57pmDraw a cross-section of the ends of the cylinder

The level of gas will form a segment of the circle, the chord being .5 ft from the centre of the circle.

Volume = area of segment x 8

to find the area of the segment, you can use formulas found in several websites, or just find it analytically

If you join radii to the ends of the chord, we have a sector.

let's find the central angle of that sector.

cosØ = .5/2.5 = .2

Ø = 78.46

so the central angle is 156.96 °

Length of chord = 2(2.5sin78.6) = 4.899

area of triangle within the sector = (1/2)(4.899)(.5) = 1.22474

area of whole circle = 2.5^2π = 19.635

area-of-sector/19.638 = 156.96/360

area of sector = 8.55899

area of segment = 8.55899 - 1.22474 = 7.33425

volume of gas in tank = 8(7.33425) = 58.674 gallons

check my arithmetic.

Nice question. I used to add a part b) to this which said.

Suppose the cylinder is turned on its end, how high will the level of gas be in the tank?

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