Homework Help: algebra 2

Posted by lisa on Friday, December 7, 2012 at 8:20pm.

check my answer please find the number of zeros(x-intercepts) y=3k^3-6k^2-45k=k(3k+9)(k-5)= k(3k^2-15k+9k-45)=k(3k^2-6k-45) or should i do it 3k(k-5) (k+3)=3k(k^2+3k-5k-15)=3k(k^2-2k-15) which on is the right one please let me know.thanks

algebra 2 - Mac, Friday, December 7, 2012 at 8:54pm
Yes you factor
3k(k-5)(k+3) and your check says you did it correctly
Now to find the zeros
Set each factor = 0. And solve
3k=0. K=0
K-5=0. K=5
K+3=0. K=-3

Answer this Question

Related Questions

7th grade pre algebra - We need assistance solving 3 + 2(k+1) = 6 + 3k I know ...
math - Prove that if p is a prime number and p is not equal to 3, then 3 divides...
Precalculus - Find the sum of 20 (summation notation symbol)k=1 then (3k-5) If ...
calculus - Consider ∞ ∑ [(3k+5)/(k²-2k)]ᵖ, ...
Pre-Algebra(please check) - Please check these simplified expressions(my answer ...
maths - The vector equations of 2 beams of light r1 and r2 in 3 dimensional ...
science - position of a particle in frame s is given by r=(6t^2-4t)i-3t^3j+3k.in...
Math - (3k^2+2)(k+5k^2)
ALG2! - -3K - 8 is less than or equal to 5k .....solve please
Math - Simplify this expression: (3k^3+2)(k+5k^2)

For Further Reading

First Name:
School Subject:
Answer: