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December 21, 2014

December 21, 2014

Posted by **lisa** on Friday, December 7, 2012 at 8:20pm.

- algebra 2 -
**Mac**, Friday, December 7, 2012 at 8:54pmYes you factor

3k(k-5)(k+3) and your check says you did it correctly

Now to find the zeros

Set each factor = 0. And solve

3k=0. K=0

K-5=0. K=5

K+3=0. K=-3

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