Posted by Victoria on Friday, December 7, 2012 at 7:57pm.
1000 mL x 0.01M = 10 millimols HAc
1000 mL x 0.1M = 100 mmols NaAc
..........Ac^- + H^+ ==> HAc
I........100.....0........10
add HNO3.........x...........
C........-x.....-x.........+x
C.......100-x....0........10+x
pH = pKa + log [(100-x)/(10+x)]
Solve for x = mmols HNO3 needed.
M = mmols/mL. You know mmols and M, solve for mL HNO3. I think the answer is about 3 mL.
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