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Posted by **Anonymous** on Friday, December 7, 2012 at 6:08pm.

Vf^2=Vi^2+2ax

0=vi^2+2(-9.8)(8.0) <----- My work

vi^2=-156.8

I don't how to solve the last step

- Physics -
**drwls**, Friday, December 7, 2012 at 6:48pmYou could solve it by taking the square root of both sides of the equation. However, your equation is wrong. You are apparently trying to apply energy conservation at the top of the trajectory, where Vf = 0. In that case, the "x" term is not 8.0 (seconds). It should be the height of the trajectory, in meters.

The rocket spends 4.0 of the 8.0 seconds going up. Decelerating at a rate g, we have

g*t = Vf = 9.8*4 = 39.2 m/s

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