Posted by lindsay on Friday, December 7, 2012 at 4:28pm.
f is undefined when x-3 is zero, because division by zero is undefined.
f = (2x+1)/(x-3)
(x-3)f = 2x+1
fx-3f = 2x+1
(f-2)x = 3f+1
x = (3f+1)/(f-2)
now plug in x(1/3) to get -6/5
dunno what h is
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