The function f:x =2x+1/x-3 and g:x =1-x/2
a. For what value of x is 'f' undefined?
b. Find 'f' inverse and hence solve f(x) =1/3.
c.Show that fg(x) -gh(x).
f is undefined when x-3 is zero, because division by zero is undefined.
f = (2x+1)/(x-3)
(x-3)f = 2x+1
fx-3f = 2x+1
(f-2)x = 3f+1
x = (3f+1)/(f-2)
now plug in x(1/3) to get -6/5
dunno what h is