Posted by lindsay on Friday, December 7, 2012 at 4:20pm.
I need to sketch the graph of t(x)=2x^2 +3x > or equal to 10xx^2. How do I work out the points to plot on the graph?

math  Steve, Friday, December 7, 2012 at 4:46pm
one way: graph both functions and see where one is above the other. Visit
http://rechneronline.de/functiongraphs/
and you can graph up to three functions at once. Set the y range for 20 to 20.
algebraic way:
2x^2+3x > 10xx^2
3x^2  7x > 0
x(3x7) > 0
either both factors are negative, or both are positive:
x is in (∞,0) U (7/3,∞)
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