Posted by **lindsay** on Friday, December 7, 2012 at 4:20pm.

I need to sketch the graph of t(x)=2x^2 +3x > or equal to 10x-x^2. How do I work out the points to plot on the graph?

- math -
**Steve**, Friday, December 7, 2012 at 4:46pm
one way: graph both functions and see where one is above the other. Visit

http://rechneronline.de/function-graphs/

and you can graph up to three functions at once. Set the y range for -20 to 20.

algebraic way:

2x^2+3x > 10x-x^2

3x^2 - 7x > 0

x(3x-7) > 0

either both factors are negative, or both are positive:

x is in (-∞,0) U (7/3,∞)

## Answer This Question

## Related Questions

- graph from asymptotes - Is it possible to roughly sketch a graph(without ...
- Calculus - Consider the function f defined by f(x)= sin x/x, x cannot equal 0 1...
- algebra - Graph the system of inequalities x (lesser or equal to sign)2 y (...
- calculus - answer the questions about the following function f(x)= 10x^2/x^4+25 ...
- word problems in algebra - The cost of producing a number of items x is given by...
- algebra - plot points (0,6) and (-3,5) plot points (0,0) and (3,1) how do i ...
- Algebra II - 1) There is a solution to x = -(y-5)^2 and x = (y -5 )^2 + 7 a) ...
- Algebra - Graph the linear equation y=4/5x+5 I know how to plot the points. I ...
- math - f(x) = x^2 + 10x + 24 =(x^2 + 10x)+ 24 =(x^2 + 10x + 25 - 25) + 24 f(x...
- how to sketch a graph of.. - Local minimum and local maximum imply that the ...

More Related Questions