Posted by **lindsay** on Friday, December 7, 2012 at 4:20pm.

I need to sketch the graph of t(x)=2x^2 +3x > or equal to 10x-x^2. How do I work out the points to plot on the graph?

- math -
**Steve**, Friday, December 7, 2012 at 4:46pm
one way: graph both functions and see where one is above the other. Visit

http://rechneronline.de/function-graphs/

and you can graph up to three functions at once. Set the y range for -20 to 20.

algebraic way:

2x^2+3x > 10x-x^2

3x^2 - 7x > 0

x(3x-7) > 0

either both factors are negative, or both are positive:

x is in (-∞,0) U (7/3,∞)

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