A charge of +3c is located 50cm from a charge of -6c
A what is the magnitude of the force exerted on each charge?
B on a drwing indicate the directioon of the forces acting on each charge
Coulombs law: Forceopposing=kQ1Q2/distance^2
notice the force opposing is negative, meaning they attract each other, so the forces are each towards the other.
To find the magnitude of the force exerted on each charge, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
Let's denote the charge of +3c as q1 and the charge of -6c as q2. The magnitude of the force, F, exerted on each charge can be calculated using the following formula:
F = k * |q1| * |q2| / r^2
Where:
- F is the magnitude of the force.
- k is Coulomb's constant, approximately equal to 9 x 10^9 Nm^2/C^2.
- |q1| and |q2| are the magnitudes of the charges, which are 3c and 6c, respectively.
- r is the distance between the charges, which is given as 50 cm or 0.5 m.
A) Calculating the force exerted on the charge of +3c:
F1 = k * |q1| * |q2| / r^2
F1 = (9 x 10^9 Nm^2/C^2) * (3c) * (6c) / (0.5m)^2
Simplifying the equation:
F1 = (9 x 10^9) * (18c^2) / 0.25m^2
F1 = (9 x 10^9) * (18) / 0.25 N
Therefore, the magnitude of the force exerted on the charge of +3c is (9 x 10^9) * (18) / 0.25 N.
B) To indicate the direction of the forces acting on each charge, we need to consider that like charges repel each other, while opposite charges attract each other.
In this case, the charge of +3c and the charge of -6c have opposite charges, therefore they will attract each other.
On a drawing, you can indicate the direction of the force acting on each charge using arrows. The force on the charge of +3c will be directed towards the charge of -6c, and the force on the charge of -6c will be directed towards the charge of +3c. You can draw arrows from the charges pointing towards each other to represent these forces.