What is the axis of symmetry for y=x^2-8x+8 equation ? Be sure to use correct notation
y = (x-4)^2 - 8
that help?
Subtract mc011-1.jpg. Identify any x-values for which the expression is undefined.
To find the axis of symmetry for the equation y = x^2 - 8x + 8, we can use the formula x = -b / (2*a).
In this case, a refers to the coefficient of the x^2 term, which is 1, and b refers to the coefficient of the x term, which is -8.
So, we substitute these values into the formula:
x = -(-8) / (2*1)
x = 8 / 2
x = 4
Therefore, the axis of symmetry for the equation y = x^2 - 8x + 8 is x = 4.