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April 25, 2014

April 25, 2014

Posted by **Andrew** on Friday, December 7, 2012 at 6:15am.

- Math -
**Reiny**, Friday, December 7, 2012 at 9:08amnumber of craftmen --- x

number of apprentices --y

500x + 100y ≥ 2000 ---> 5x + y ≥ 20 for ceramic

100x + 200y ≥ 1600 ---> x + 2y ≥ 16 for vinyl

cost = 200x + 120y

sketch the first two relations in x and y

we need the closest integer-point to their intersection point of (2.67 , 6.67)

which would be (3,7)

So 3 craftsmen and 7 apprentices would do the job and be cheapest.

check:

with (3,8) --> 1500+800 or 2300 ceramic, job done

---------> 300+1600 or 1900 vinyl, job done

cost = 200(3) + 120(8) = $1560

with (3,7) --> 1500+700= 2200 ceramics, job done

----------> 300+ 1400= 1700 vinyl, job done

cost = 200(3) + 120(7) = $1440

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