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January 28, 2015

January 28, 2015

Posted by **Tatjana** on Thursday, December 6, 2012 at 11:33pm.

- calculus -
**Steve**, Thursday, December 6, 2012 at 11:45pmthe height h(t) is

h(t) = vt-4.9t^2

h=0 when t=4, so

4v-4.9*16 = 0

v = 19.6

h(t) = 19.6t - 4.9t^2

max h at t=2 because of symmetry

h(2) = 19.6*2 - 4.9*4 = 19.6

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