Posted by **Patrick** on Thursday, December 6, 2012 at 8:35pm.

given the reacting system: H2 (G) + I2(G) ---> 2HI(g) Keq= 64

Equal moles of H2, I2, and HI are placed in a 1.0 L container. Use calculations to determine the direction the reaction will proceed in order to reach equilibirum

- Chemistry 12 -
**DrBob222**, Friday, December 7, 2012 at 5:17pm
..........H2 + I2 ==> 2HI

Keq = 64 = (HI)^2/(H2)((I2)\

Try any number, say 1

Qrxn = (1)^2/1*1 = 1

Try 2.

(2^2)/2*2 = 1

Try 3.

3^2/3*3 = 1

Get the picture?

So Q = 1; K = 64. That means (from Q) that the numerator is too small and the denominator is too large (that's the only way you can get a smaller number than 64). So H2 and I2 are too large; HI is too small. Which way MUST it go?

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