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March 29, 2015

Posted by **michelle** on Thursday, December 6, 2012 at 6:26pm.

2515 rpm 23 cm

max speed of the piston 30.28757 m/s

What is the maximum force acting on the

piston when the engine is running at the same rate? Answer in units of N

- physics help please! -
**Damon**, Thursday, December 6, 2012 at 6:37pmfind the frequency in Hz

f = 2515 rev/min (1 min/60 s) = 41.92 Hz

y = (0.23/2)sin (2 pi f t)

y = 0.115 sin 263 t

v = (0.115)(263) cos 263 t so yes max of 30.29 m/s

a = -30.29(263)sin 263 t

so max a = 7966 m/s^2

F = m a = 1.7*7966 = 13543 Newtons

- physics help please! -
**michelle**, Thursday, December 6, 2012 at 8:52pmthank you!!!!!

i must have messed up on my calculations

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