Posted by michelle on Thursday, December 6, 2012 at 6:26pm.
The motion of a piston in an auto engine is simple harmonic. The piston travels back and forth over a distance of 23 cm, and the piston has a mass of 1.7 kg.
2515 rpm 23 cm
max speed of the piston 30.28757 m/s
What is the maximum force acting on the
piston when the engine is running at the same rate? Answer in units of N

physics help please!  Damon, Thursday, December 6, 2012 at 6:37pm
find the frequency in Hz
f = 2515 rev/min (1 min/60 s) = 41.92 Hz
y = (0.23/2)sin (2 pi f t)
y = 0.115 sin 263 t
v = (0.115)(263) cos 263 t so yes max of 30.29 m/s
a = 30.29(263)sin 263 t
so max a = 7966 m/s^2
F = m a = 1.7*7966 = 13543 Newtons 
physics help please!  michelle, Thursday, December 6, 2012 at 8:52pm
thank you!!!!!
i must have messed up on my calculations