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Posted by on Thursday, December 6, 2012 at 6:26pm.

The motion of a piston in an auto engine is simple harmonic. The piston travels back and forth over a distance of 23 cm, and the piston has a mass of 1.7 kg.
2515 rpm 23 cm
max speed of the piston 30.28757 m/s

What is the maximum force acting on the
piston when the engine is running at the same rate? Answer in units of N

  • physics help please! - , Thursday, December 6, 2012 at 6:37pm

    find the frequency in Hz
    f = 2515 rev/min (1 min/60 s) = 41.92 Hz

    y = (0.23/2)sin (2 pi f t)
    y = 0.115 sin 263 t
    v = (0.115)(263) cos 263 t so yes max of 30.29 m/s
    a = -30.29(263)sin 263 t
    so max a = 7966 m/s^2
    F = m a = 1.7*7966 = 13543 Newtons

  • physics help please! - , Thursday, December 6, 2012 at 8:52pm

    thank you!!!!!
    i must have messed up on my calculations

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