PHYSICS  PLEASE HELP
posted by Anonymous .
Three objects are moving along a straight line as shown in the figure. Taking the positive direction to be to the right, what is the total momentum of this system?
Pos > 5.00 m/s, 8.00 kg
Neg < 4.00 m/s, 15.00 kg
Pos > 2.00 m/s, 3.00 kg
A) 14 kg m/s
B) +106 kg m/s
C) +14 kg m/s
D) 106 kg m/s
E) 0 kg m/s

add the momentums up, to the left is negataive. I will be happy to critique your work. You can do it in your head. What is 4660?

total momentum = m1(v1)+m2(v2)+m3(v3)
total momentum = [(5)8]+[(4)15]+[(2)3]
total momentum = (40)+(60)+(6)
total momentum = (20)+(6) = 14
Answer: A