Posted by **Josh** on Thursday, December 6, 2012 at 12:36pm.

What is the solution set of the equation?

I know the answer is {-1} I just don't know how to get there.

X^2-16 x-3

--------- = ------- -1

(x+4)(x+2) (x+2)

- Algebra 2 Rational Equations -
**Anonymous**, Thursday, December 6, 2012 at 12:40pm
Get a common denominator

Drop it

Solve the numerator

Check your answer- if the answer makes the denominator equal to 0, then drop it (excluded value)

- Algebra 2 Rational Equations -
**Anonymous**, Thursday, December 6, 2012 at 12:41pm
Do not forget 1 needs a common denominator

- Algebra 2 Rational Equations -
**Anonymous**, Thursday, December 6, 2012 at 12:48pm
X-4=x-3-(x+2)

Common den is x+2

On the first factor out x+4

- Algebra 2 Rational Equations -
**Steve**, Thursday, December 6, 2012 at 3:01pm
(x^2-16)/(x+4)(x+2) - (x-3)/(x+2) + 1 = 0

place all over a common denominator (x+4)(x+2)

(x^2-16) - (x-3)(x+2) + (x+4)(x+2)

----------------------------------- = 0

(x+4)(x+2)

(x^2-16-x^2+x+6+x^2+6x+8)/(x+4)(x+2) = 0

(x^2+5x+4)/(x+4)(x+2) = 0

(x+4)(x+1)/(x+4)(x+2) = 0

(x+1)/(x+2) = 0

So, f(x) = 0 when x = -1

Note that the domain excludes x = -4 and -2

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