Posted by **Anonymous** on Thursday, December 6, 2012 at 6:09am.

a bridge is 10 m. above a canal. A motorboat going 3 m/sec passes under the center of the bridge at the same instant that a woman walking 2 m/sec reaches that point. How rapidly are they separating 3 sec. later?

- calculus -
**Reiny**, Thursday, December 6, 2012 at 8:05am
At a time of t seconds

let the distance covered by the boat be 3t m

let the distance covered by the woman be 2t m

If D is the distance between them,

D^2 = (3t)^2 + 10^2 + (2t)^2

D^2 = 13t^2 + 100

2D dD/dt = 26t

dD/dt = 13t/D

at 3 seconds D^2 = 81 + 100 + 16 = 197

D = √197

so at 3 seconds , dD/t = 13(3)/√197 = 2.7786

= appr 2.8 m/s

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