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March 26, 2017

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Suppose that absorbances of several solutions were measured at 545 nm. What is the frequency of this wavelength? What is the energy of this wavelength? (h=6.626 times 10^-34J*S)

  • Chemistry - ,

    c = freq x wavelength.
    c = 3E8 m/s
    freq = ? in Hz.
    wavelength = 545 nm x 10^-9 m

    For E in J = hc/wavelength.

  • Chemistry - ,

    What is the freq? You got C=2x10^8m/s but you don't have the freq.

  • Chemistry Someone Check for me - ,

    What did you use for the freq?

  • Chemistry - ,

    Isn't the problem asking for frequency? You use c = f*w to solve for f.
    And I don't see anywhere that I have 2E8 m/s.
    c = f*w
    3E8 = f*545E-9
    Solve for f.

  • Chemistry - ,

    Is F=5.55*10^14Hz?

  • Chemistry - ,

    close. I obtained 5.504E14 Hz which I would round to 5.50E14 Hz to three significant figures..

  • Chemistry - ,

    For the energy is it around 3.647x10^-19J? And how did you know that c=3*10^8m/s?

  • Chemistry - ,

    c is the speed of light. Look in your text for a table of physical constants and you will find the speed of light as 299,792,458 m/s which most of us round to 3E8 m/s most of the time.
    I found E to be the same number you have.

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