How many mL of concentrated HNO3 (conc. HNO3 is 16 Molar)will be needed to make 1.25 Liters of 9 Molar HNO3?
c1v1 = c2v2
c = concn
v = volume
16M x v1 = 9M x 1.25L
Solve for v1 in L.
To find out how many milliliters of 16 Molar concentrated HNO3 are needed to make 1.25 Liters of 9 Molar HNO3, we can use the following formula:
(concentration of solute A) x (volume of solute A) = (concentration of solute B) x (volume of solute B)
In this case, solute A is the concentrated HNO3 with a concentration of 16 Molar, and solute B is the final 9 Molar HNO3 solution.
We can rearrange the formula to solve for the volume of solute A:
(volume of solute A) = [(concentration of solute B) x (volume of solute B)] / (concentration of solute A)
Plugging in the given values:
(volume of solute A) = [(9 Molar) x (1.25 Liters)] / (16 Molar)
Simplifying:
(volume of solute A) = 0.5625 Liters or 562.5 mL
Therefore, you would need 562.5 mL of concentrated HNO3 to make 1.25 Liters of 9 Molar HNO3.