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April 19, 2014

Posted by **Tia** on Wednesday, December 5, 2012 at 10:01pm.

be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?

- Help math -
**Anonymous**, Wednesday, December 5, 2012 at 10:04pmLooks right to me

- Help math -
**Tia**, Wednesday, December 5, 2012 at 10:22pmThank you !

- Help math -
**Steve**, Wednesday, December 5, 2012 at 11:17pmnot to me. 2 appears twice, so you'd have 2^2 * 2^3 = 2^5

- Help math Steve help -
**Kristin & Tia**, Wednesday, December 5, 2012 at 11:41pmWhat does it multiply too? equal too?

confused now.

How do I write this then ??

"So is this right for prime factorization

be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ? "

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