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Posted by on Wednesday, December 5, 2012 at 10:01pm.

So is this right for prime factorization
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?

  • Help math - , Wednesday, December 5, 2012 at 10:04pm

    Looks right to me

  • Help math - , Wednesday, December 5, 2012 at 10:22pm

    Thank you !

  • Help math - , Wednesday, December 5, 2012 at 11:17pm

    not to me. 2 appears twice, so you'd have 2^2 * 2^3 = 2^5

  • Help math Steve help - , Wednesday, December 5, 2012 at 11:41pm

    What does it multiply too? equal too?
    confused now.

    How do I write this then ??

    "So is this right for prime factorization
    be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ? "

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