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December 18, 2014

December 18, 2014

Posted by **Tia** on Wednesday, December 5, 2012 at 10:01pm.

be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?

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**Anonymous**, Wednesday, December 5, 2012 at 10:04pmLooks right to me

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**Tia**, Wednesday, December 5, 2012 at 10:22pmThank you !

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**Steve**, Wednesday, December 5, 2012 at 11:17pmnot to me. 2 appears twice, so you'd have 2^2 * 2^3 = 2^5

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**Kristin & Tia**, Wednesday, December 5, 2012 at 11:41pmWhat does it multiply too? equal too?

confused now.

How do I write this then ??

"So is this right for prime factorization

be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ? "

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