If 1 antacid tab neutralizes 6.84 mmol of HCL (36.46 g/mol). How many tabs are needed to neutralize 125 mL of stomach acid. Assume [H3O+] = 0.10 mmol/mL.

I have no idea where to go with this. Any formula would help

How much acid do you have in 125 mL of 01M acid? That's 125 mL x 0.1M = 12.5 mmols.

6.84 mmols/tab x # tablets = 12.5 mmols.
Solve for # tablets

Thanks so much. I had come up with 12.5 mmols, but didn't know what to do with it.

To solve this problem, we need to calculate the amount of HCl in 125 mL of stomach acid and then determine how many antacid tablets are needed to neutralize that amount of HCl.

First, we need to find the amount of HCl in 125 mL of stomach acid. We are given that the concentration of H3O+ (which is equivalent to HCl) is 0.10 mmol/mL. Therefore, the amount of HCl in 125 mL can be calculated using the formula:

Amount of HCl = Concentration of HCl * Volume of stomach acid

Amount of HCl = 0.10 mmol/mL * 125 mL

Next, we can convert the amount of HCl from mmol to g using the molar mass of HCl, which is 36.46 g/mol. We can use the formula:

Amount of HCl (g) = Amount of HCl (mmol) * Molar mass of HCl (g/mol)

Now that we know the amount of HCl in grams, we can determine the number of antacid tablets needed to neutralize this amount. We are given that 1 antacid tablet neutralizes 6.84 mmol of HCl. To find the number of tablets, we will use the formula:

Number of tablets = Amount of HCl (g) / Amount of HCl neutralized by 1 tablet (mmol)

Now let's calculate step by step:

Step 1: Calculate the amount of HCl in 125 mL of stomach acid.
Amount of HCl = 0.10 mmol/mL * 125 mL
Amount of HCl = 12.5 mmol

Step 2: Convert the amount of HCl from mmol to grams.
Amount of HCl (g) = 12.5 mmol * (36.46 g/mol)
Amount of HCl (g) = 455.75 g

Step 3: Determine the number of antacid tablets.
Number of tablets = 455.75 g / 6.84 mmol
Number of tablets ≈ 66.60

Therefore, approximately 66.60 antacid tablets are needed to neutralize 125 mL of stomach acid.