Posted by **anonymous** on Wednesday, December 5, 2012 at 9:06pm.

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 300 N applied to its edge causes the wheel to have an angular acceleration of 1.072 rad/s2.

(a) What is the moment of inertia of the wheel?

(b) What is the mass of the wheel?

(c) If the wheel starts from rest, what is its angular velocity after 4.00 s have elapsed, assuming the force is acting during that time?

- Physics -
**Jennifer**, Friday, December 7, 2012 at 5:06pm
torque = F*r = I*alpha

where F = force, r = radius, I = moment of inertia, and alpha is angular acceleration.

a)

For a cylinder I = 1/2*m*r^2, where m is mass

b)

F*r = 1/2*m*r^2*alpha

Substitute values from the problem to find m

c) omega = alpha*t

where omega is angular velocity

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