Posted by **Johnvon** on Wednesday, December 5, 2012 at 8:35pm.

Consider a simple pendulum of length 1.1 m with

m = 2.9 kg.

If the amplitude of the oscillation is 0.11 m (as measured along the circular arc along which it moves), what is the total mechanical energy of the oscillator?

____ Joules

- Physics 1 -
**Jennifer**, Friday, December 7, 2012 at 5:19pm
When all the mechanical energy is kinetic energy, the energy is

1/2*m*v^2 = 1/2*m*omega^2*r^2

where m is the mass, r is the radius, and omega is the angular velocity; For a pendulum, the angular velocity is given by omega = (g/r)^0.5

## Answer This Question

## Related Questions

- physics - A simple pendulum is made from a bob of mass 0.04 kg suspended on ...
- physics - consider a simple harmonic oscillation with m=0.5kg, k=10N/m and ...
- physics - Consider a simple harmonic oscillation with m=0.5kg, k=10N/m and ...
- Physics - The length of a simple pendulum is 0.72 m, the pendulum bob has a mass...
- physics - A simple pendulum is made from a bob of mass 0.04 kg suspended on a ...
- physics - consider a simple harmonic oscillation with m=0.5kg,k=10N/m and ...
- College Physics - Can someone check my answers for two and help me with the ...
- physics - A simple harmonic oscillator consists of a 1.1 kg block attached to a ...
- physics - Refer to the equation you derived in exercise (4). Assume that 1 y = 0...
- physics - A simple harmonic oscillator consists of a 1.1 kg block attached to a ...

More Related Questions