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November 26, 2014

November 26, 2014

Posted by **Johnvon** on Wednesday, December 5, 2012 at 8:35pm.

m = 2.9 kg.

If the amplitude of the oscillation is 0.11 m (as measured along the circular arc along which it moves), what is the total mechanical energy of the oscillator?

____ Joules

- Physics 1 -
**Jennifer**, Friday, December 7, 2012 at 5:19pmWhen all the mechanical energy is kinetic energy, the energy is

1/2*m*v^2 = 1/2*m*omega^2*r^2

where m is the mass, r is the radius, and omega is the angular velocity; For a pendulum, the angular velocity is given by omega = (g/r)^0.5

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