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posted by Amy on Wednesday, December 5, 2012 at 8:08pm.
Show that one mole of KCLO3 contains 122.55 grams. 2 KCLO3(s)->2 KCL(s) + 3 O2(g)
K = 39.1 or thereabouts Cl = 35.4 about O = 3*16 = 48 about. You can look up these numbers and add them.
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