Posted by Anon on Wednesday, December 5, 2012 at 8:02pm.
I don't know what "in the option" means. Is that 15.8 mg/L the concn in the 100 mL? If so then
15.8 x 100/25 = ? mg/L in the lake.
Don't you have times 100/25 by 1000mL/1L to get it to mg/L?
Related Questions
Chemistry - Concentration 15.8 mg/L Final Volume 100.0 mL What is the ...
chemistry - a ferric phosphate solution is prepared by adding 2.4 g of ferric ...
Chemistry ...ASAP please - a ferric phosphate solution is prepared by adding 2.4...
osu - a 50.0 ml sample of a 15% (m/v) solution of H2SO4 is added to water to ...
BioChem - If you want to determine the actual salicylate concentration for a ...
Chemistry - Water treatment plans must reduce phosphate levels to 3.2 micromoles...
Chemistry - A 50 mL sample of 8% (m/v) NaOH is diluted with water so that the ...
Chemistry - A solution is prepared by dissolving 15.6 g ammonium sulfate in ...
Chemistry - A 5 mL sample of 50% (m/v) acetic acid (Hc2H3O2) solution is added ...
chemistry - A 150.0-mL sample of Solution A is diluted to a total volume of 423 ...
For Further Reading