Posted by nelia on Wednesday, December 5, 2012 at 5:43pm.
help balancing S+HNO3=H2SO4=N02=H2O
I suppose we are assuming that the impurities were unchanged as the Mg was oxidized.
2Mg + O2 ==> 2MgO
mols O2 = 0.090/32 = about 0.0028 but you should redo and get a more accurate answer.
Convert mols O2 to mols Mg, the to g Mg.
mols O2 x (2 mols Mg/1 mol O2) = aboaut 0.0056 mols Mg.
0.0056 mols Mg x atomic mass Mg = about 0.137 g Mg.
So impurities = 0.144 - 0.137 = about 0.007g.
Then % impurities = (0.007/0.144)*100 = ?
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