posted by Anonymous on .
Particle 1 and particle 2 have masses of m1 = 1.5×10-8 kg and m2 = 6.2×10-8 kg, but they carry the same charge q. The two particles accelerate from rest through the same electric potential difference V and enter the same magnetic field, which has a magnitude B. The particles travel perpendicular to the magnetic field on circular paths. The radius of the circular path for particle 1 is r1 = 12 cm. What is the radius (in cm) of the circular path for particle 2?
m₁v₁²/2 =qU => v₁ =sqrt(2qU/m₁)
m₂v₂²/2 =qU => v₂=sqrt(2qU/m₂)
in magnetic field:
a=v²/R, α=90°, sin90°=1