Posted by **amy** on Wednesday, December 5, 2012 at 4:22pm.

A board of directors consisting of eight members is to be chosen from a pool of 28 candidates. The board is to have a chairman, a treasurer, a secretary, and five other members. In how many ways can the board of directors be chosen?

- math -
**Anonymous**, Wednesday, December 5, 2012 at 5:36pm
For permutations without repetitions, the formula is n!/((n-r)!), where n is the number of things to choose from, and you choose r of them There is no repetition, and order matters.

Think about it this way. You have 28 candidates total. For the position of chairman, there are 28 possible people. After you select one person for chairmen, there are 27 people left - 27 possible people.

With each position that is filled, you have one less person for the job. At the end, you'll have all 8 positions filled, and 20 people left over.

So then we have 28!/((28-8)!) = 28x27x26x25x24x23x22x21. That should give you your answer.

## Answer this Question

## Related Questions

- math - there are 6 members on a board of directors .if they must elect a ...
- Math Word Problem - There are 10 members on a board of directors. If they must ...
- Math - A corporation has 7 members on its board of directors. How many different...
- Finance - Blue Moon Corporation has one million shares of common stock ...
- MATH - Permutation For a segment of a radio, a disc jockey can play 7 songs. If ...
- Math - There are 8 members on a board of directors. If they must form a ...
- Math - There are 8 members on a board of directors. If they must form a ...
- MATH Prob. - There are 8 members on a board of directors. If they must form a ...
- Math - There are 8 members on a board of directors. If they musform a ...
- STATS - the following case occured in Gainsville, Florida. the eight-member ...

More Related Questions