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Chemistry

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How will overshooting the end point of an acid-base titration by adding too much base to KHP affect the calculated molarity of the base?
I would think you would need to add more KHP, then more base to bring it to the endpoint. So the molarity calculated should be the same.
Is that correct?

  • Chemistry - ,

    Or if you didn't correct this error, the molarity of the base would be higher than it should be.
    Is that correct?

  • Chemistry - ,

    Oops, I mean the molarity would decrease because moles base / larger quantity in L = a small # therefore decreased molarity.
    Correct?

  • Chemistry - ,

    I find it helpful to write each step of the procedure and see how the question affects each.
    1. mols KHP = grams/molar mass
    2. mols NaOH = mols KHP
    3. M NaOH = mols NaOH/L NaOH

    So you did steps 1 and 2 right but on 3 added too much L NaOH. That's in the denominator, too big number means too small M.

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