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pHYSICS

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You're working on an experiment to determine the calorie content of peanuts. To do this, you burn a peanut beneath a container of water, and measure the water's temperature change. Suppose the peanut has a mass of 0.59 g, and the water has a mass of 63.5 g. The water's temperature rises from 21.2oC to 49.7oC.

  • pHYSICS -

    water: Q=cmΔT=4180•0.063•(49.7-21.2)=7505.19 J=1792.6 cal
    peanut: 0.59 g (or kg???)

    calorie content = 7505.19/0.59•10⁻³ J/kg=1792.6 /0.59•10⁻³ cal/kg =

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