Posted by darian on Wednesday, December 5, 2012 at 1:09pm.
If the top of the pole moved from P to Q, and the base of the pole is at A, and the observation point is at B,
sinQ/30 = sin45/25
sinQ = 0.848
Q = 58°
Now you have two angles of triangle ABQ, so you know angle θ=QAB.
PQ^2 = 25^2 + 25^2 - 2(25)(25)cos(90-θ)
= 1250 - 1250sinθ
= 1250(1-sin(pi-(45+Q))
= 1250(1-sin(45°+58°))
= 32
PQ = √32 = 5.66
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