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December 21, 2014

December 21, 2014

Posted by **darian** on Wednesday, December 5, 2012 at 1:09pm.

- math -
**Steve**, Wednesday, December 5, 2012 at 2:41pmIf the top of the pole moved from P to Q, and the base of the pole is at A, and the observation point is at B,

sinQ/30 = sin45/25

sinQ = 0.848

Q = 58°

Now you have two angles of triangle ABQ, so you know angle θ=QAB.

PQ^2 = 25^2 + 25^2 - 2(25)(25)cos(90-θ)

= 1250 - 1250sinθ

= 1250(1-sin(pi-(45+Q))

= 1250(1-sin(45°+58°))

= 32

PQ = √32 = 5.66

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