The kindergarten has a box of blocks.Some blocks are red,some yellow and some are blue.1/2 of the blocks are red,1/4 of the blocks are yellow and 24 of the blocks are blue.How many blocks are in the box?
1/4x = 24
x = 24/(1/4)
x = 24 * (4/1)
x = 96
There are 50 blocks in the box
Let's assume the total number of blocks in the box is "x".
According to the given information:
1/2 of the blocks are red, which is equal to (1/2)x.
1/4 of the blocks are yellow, which is equal to (1/4)x.
There are 24 blue blocks.
Now, let's add up all the blocks:
(1/2)x + (1/4)x + 24 = x
To solve this equation, we need to get rid of the fractions by finding a common denominator. The common denominator in this case is 4. Multiply each part of the equation by 4:
2(1/2)x + 4(1/4)x + 4(24) = 4x
2x + x + 96 = 4x
Now, subtract 2x and x from both sides of the equation:
96 = 4x - 3x
Simplifying further, we have:
96 = x
Therefore, the total number of blocks in the box is 96.
To find out how many blocks are in the box, we can use the given fractions of each color and the total number of blue blocks as a reference.
Let's allocate variables to represent the unknowns:
Let R = the number of red blocks
Let Y = the number of yellow blocks
Let B = the number of blue blocks
Let T = the total number of blocks in the box
From the given information:
1/2 of the blocks are red, so R = 1/2 * T
1/4 of the blocks are yellow, so Y = 1/4 * T
The given number of blue blocks is 24, so B = 24.
Since the total number of blocks is the sum of the blocks of each color:
T = R + Y + B
Substituting the values we know:
T = (1/2 * T) + (1/4 * T) + 24
To solve this equation, we can manipulate it to isolate T:
T = (1/2 * T) + (1/4 * T) + 24
Multiplying the fractions by their denominators:
T = (2/4 * T) + (1/4 * T) + 24
Combining like terms:
T = (3/4 * T) + 24
Subtracting (3/4 * T) from both sides:
T - (3/4 * T) = 24
(4/4 * T) - (3/4 * T) = 24
(1/4 * T) = 24
Multiplying both sides by 4 to remove the fraction:
4 * (1/4 * T) = 4 * 24
T = 96
Therefore, there are 96 blocks in the box.