three bugs that are connected by a mass less spider silk are pulled along a frictionless table top. The first bug has a mass of 1.5 g, the second, 2.0 g, and the third, .75 g. The spider pulling them exerts a force of 0.011 N. What is the acceleration of each bug?

a=F/(m1+m2+m3)

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To find the acceleration of each bug, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

First, let's find the total mass of the bugs. We add the masses of all three bugs:

Total mass = 1.5 g + 2.0 g + 0.75 g = 4.25 g

Next, we convert the total mass from grams to kilograms, since the SI unit for mass is kilograms:

Total mass = 4.25 g = 0.00425 kg (dividing by 1000)

Now, we can calculate the acceleration. The net force acting on the bugs is the force exerted by the spider. Therefore, we have:

Net force = 0.011 N

Using Newton's second law of motion, we have:

Net force = mass × acceleration

Rearranging the formula, we can solve for the acceleration:

Acceleration = Net force / mass

Now, we can calculate the acceleration for each bug:

Acceleration of the first bug = Net force / mass of the first bug
Acceleration of the first bug = 0.011 N / 0.0015 kg (converting 1.5 g to kg)

Acceleration of the second bug = Net force / mass of the second bug
Acceleration of the second bug = 0.011 N / 0.0020 kg (converting 2.0 g to kg)

Acceleration of the third bug = Net force / mass of the third bug
Acceleration of the third bug = 0.011 N / 0.00075 kg (converting 0.75 g to kg)

Calculating each of these, we find the values for the three bug's accelerations.