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April 20, 2014

April 20, 2014

Posted by **Khan** on Wednesday, December 5, 2012 at 11:30am.

The acceleration of gravity is 9.8 m/s2 .

If his downward motion is stopped 3.58 s after he enters the water, what average upward force did the water exert on him?

I already calculated that his velocity before hitting the water is 14.277 m/s.

- Physics -
**Elena**, Wednesday, December 5, 2012 at 4:16pmmgh=mv₀²/2

v₀=sqrt(2gh)=sqrt(2•9.8•10.4)=14.28 m/s

v= v₀-at, v=0 =>

a= v₀/t = 14.28/3.58 =4 m/s²

F=ma=68.2•4=272.8 N

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