Thursday
March 23, 2017

Post a New Question

Posted by on Wednesday, December 5, 2012 at 11:30am.

A high diver of mass 68.2 kg jumps off a board 10.4 m above the water.
The acceleration of gravity is 9.8 m/s2 .
If his downward motion is stopped 3.58 s after he enters the water, what average upward force did the water exert on him?
I already calculated that his velocity before hitting the water is 14.277 m/s.

  • Physics - , Wednesday, December 5, 2012 at 4:16pm

    mgh=mv₀²/2
    v₀=sqrt(2gh)=sqrt(2•9.8•10.4)=14.28 m/s
    v= v₀-at, v=0 =>
    a= v₀/t = 14.28/3.58 =4 m/s²
    F=ma=68.2•4=272.8 N

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question