posted by sarah on .
what is the pH of the solution formed when 25 mL of 0.173 M NaOH is added to 35 mL of 0.342 M HCl?
millimols HCl = 35 mL x 0.342M = ?
mmols NaOH = 5 x 0.173 = ?
Calculate each, determine the one in excess, calculate the amount in excess, then if acid pH = -log(H^+) or if basic then pOH = -log(OH^-) and convert to pH by pH + pOH = pKw = 14.