Thursday
March 23, 2017

Post a New Question

Posted by on Wednesday, December 5, 2012 at 11:26am.

Jess is running around a circular track, one lap every 40 seconds. Mackenzie is also running at a constant speed around the same track, but in the opposite direction. They meet every 15 seconds. How many seconds does it take Mackenzie to do one lap?

  • Math - , Friday, December 7, 2012 at 3:28pm

    d1 = (15s/40s) * 1Lap = 15/40=3/8 Lap =
    Jess' distance.

    d1 + d2 = i Lap.
    3/8 + d2 = 1
    d2=1 - 3/8 = 5/8 Lap in 15s.=Mackenzie'
    distance.

    T = 15s/(5/8)Lap = 15 * 8/5 = 24 s/Lap.
    = Mackenzie' speed.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question