Stacy has .55kg water sample at 1 atm pressure and 40 degrees celsius. She heats it to 90 degrees Celsius, maintaining constant pressure. How much heat was absorbed by the solution during the course of this operation? (CP of H2O (l) = 4.18 J/g )

To calculate the amount of heat absorbed by the water sample, we can use the equation:

Q = m * Cp * ΔT

where Q is the amount of heat absorbed, m is the mass of the sample, Cp is the specific heat capacity of water, and ΔT is the change in temperature.

First, let's convert the mass of the sample from kg to grams:

m = 0.55 kg * 1000 g/kg = 550 g

Next, we need to calculate the change in temperature (ΔT):

ΔT = final temperature - initial temperature
= 90°C - 40°C
= 50°C

Now we can plug these values into the equation:

Q = 550 g * 4.18 J/g°C * 50°C

Calculating this expression will give us the amount of heat absorbed by the solution.