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December 19, 2014

December 19, 2014

Posted by **preet0099 help me !** on Wednesday, December 5, 2012 at 7:49am.

x^2(a^2+b^2)+2x(ac+bd)+(C^2+d^2)=0 has no real roots.

- maths -
**Steve**, Wednesday, December 5, 2012 at 11:24amthe discriminant is

4(ac+bd)^2 - 4(a^2+b^2)(c^2+d^2)

junk the 4, as it does not change things, and you have

a^2c^2 + 2abcd + b^2d^2 - a^2c^2 - a^2d^2 - b^2c^2 - b^2d^2

= 2abcd - a^2d^2 - b^2c^2

= -(ad-bc)^2

since that is always negative, there are no real roots.

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