a negative charge 5.0 X 10^-4 C exerts a repulstio force of 7.0 N .on second charge away 0.05 m away.

what is the sign and magnitude of the second charge

find the force exerted by proton and the electron in a hydrogen atom they are 5.0 X 10^-19 coulomb

To determine the sign and magnitude of the second charge, we can use Coulomb's law, which states that the force between two charges is given by:

F = (k * |q1 * q2|) / r^2

Where:
F is the force between the charges,
k is the electrostatic constant (9.0 x 10^9 Nm^2/C^2),
q1 and q2 are the charges, and
r is the distance between the charges.

Given:
Charge q1 = -5.0 x 10^-4 C (negative charge),
Force F = 7.0 N, and
Distance r = 0.05 m.

We can rearrange the Coulomb's law equation to solve for the magnitude of the second charge (|q2|):

|q2| = (F * r^2) / (k * |q1|)

Substituting the given values:

|q2| = (7.0 N * (0.05 m)^2) / (9.0 x 10^9 Nm^2/C^2 * 5.0 x 10^-4 C)

Calculating:

|q2| = 0.07 C

Since the magnitude of the charge is positive, the second charge is positive.

Therefore, the sign of the second charge is positive, and the magnitude of the second charge is 0.07 C.

To find the sign and magnitude of the second charge, we can use Coulomb's Law. Coulomb's Law states that the electric force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, it can be represented as:

F = k * (|q1| * |q2|) / r^2

Where:
F = electric force between the charges
k = Coulomb's constant (8.99 x 10^9 N m^2/C^2)
q1 and q2 = charges of the two objects
r = distance between the charges

Given:
Charge 1 (q1) = -5.0 x 10^-4 C (negative charge)
Force (F) = 7.0 N
Distance (r) = 0.05 m

We can rearrange Coulomb's Law to solve for the magnitude of the second charge (|q2|):

|q2| = (F * (r^2)) / (k * |q1|)

Let's plug in the given values to calculate the magnitude of the second charge:

|q2| = (7.0 N * (0.05 m)^2) / ((8.99 x 10^9 N m^2/C^2) * |-5.0 x 10^-4 C|)

Upon evaluating this equation, we find that the magnitude of the second charge |q2| is approximately 7.79 x 10^-5 C.

Now, let's determine the sign of the second charge. Since we know that the force between the two charges is repulsive (positive), we can conclude that the second charge must have the opposite sign of the first charge. Therefore, the sign of the second charge is positive.