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An object weighing 400.0g in air is immersed in water after being tied to a string connected to a balance. The scale now reads 364.6g.
a.) Find the loss of weight(in gram of weight) when completely submersed in water.
b.) Find the volume of the object in cm^3 and in m^3.
c.) Find the density of the object in g/cm^3 and in kg/m^3.
d.) Find the buoyant force in N on the object when it is completely submerged in water.

  • Physics -

    a) Subtract 364.6 g from the weight in air. You get 35.4 g (weight)
    b) Divide the weight loss (from a) by the weight density of water, 1.0 g/cm^3. Answer: 35.4 cm^3
    c) Divide the object mass (which part (a) calls the weight) by the Volume from (b). You get 11.3 g/cm^3
    d) The buoyant force in (a) is in grams weight. It equals the mass in grams. Convert to mass in kg and multiply that by g (9.8 m/s^2) for buoyant force in Newtons.

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